LeetCode： check_if_exist

Question

Given an array arr of integers, check if there exists two integers N and M such that N is the double of M ( i.e. N = 2 * M).

More formally check if there exists two indices i and j such that :

i != j 0 <= i, j < arr.length arr[i] == 2 * arr[j]

Example 1:

Input: arr = [10,2,5,3]

Output: true

Explanation: N = 10 is the double of M = 5,that is, 10 = 2 * 5.

Example 2:

Input: arr = [7,1,14,11]

Output: true

Explanation: N = 14 is the double of M = 7,that is, 14 = 2 * 7.

Example 3:

Input: arr = [3,1,7,11]

Output: false

Explanation: In this case does not exist N and M, such that N = 2 * M.

Solution#1

def check_if_exist(arr)
  arr.delete(0) if arr.count(0) == 1

  arr.each do |n|
    double = n * 2
    arr.each do |num|
      return true if double == num
    end
  end
  return false
end