LeetCode: Find Numbers with Even Number of Digits

Question

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.

Example 2:
Input: nums = [555,901,482,1771]
Output: 1
Only 1771 contains an even number of digits.

Solution

def find_numbers(nums)
  counter = 0
  nums.each do |num|
    counter += 1 if num.to_s.length.even?
  end
  counter
end